You can get a rough idea of if this is fair by modelling it:
Suppose Bercow picked order of questions at random. About 1 in 6 questions on the 26th were supportive. A geometric distribution gives the expected number of non-supportive questions before a supportive one (1/) twitter.com/MattChorley/st…
In reply to @christianp
Probability of success, p = 1/6. The expected number of failures before a success is (1-p)/p = 5. So 31 questions before a supportive MP was called suggests that Bercow wasn't picking questions at random. (2/2)
In reply to @christianp
Picking at random isn't a good way of doing things, as a speaker. I know next to nothing about parliamentary procedure, but I assume he'd use some judgement to pick questions so as to ensure the range of opinions is heard. There might be lots of competing non-supportive views