In reply to @icecolbeveridge

@icecolbeveridge @DavidKButlerUoA I think you have in spirit the same solution as me. I spent most of my time unsure if I could expand out the dot product, and then wondering where I'd used the isosceles property before remembering a.a = |a|², so I need |a| = |b| (I first had a.a = 1)

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