In reply to @Gopesh_Krishna
@Gopesh_Krishna @MARitchings in base b, 1248 = 1*b^3+2*b^2+4*b+8 = (b+2)(b^2+4). If that's a power of 2, then each factor must be also.
In reply to @Gopesh_Krishna
@Gopesh_Krishna @MARitchings in base b, 1248 = 1*b^3+2*b^2+4*b+8 = (b+2)(b^2+4). If that's a power of 2, then each factor must be also.