In reply to @icecolbeveridge
@icecolbeveridge I might be evil - currently computing hashes of all 8-digit numbers to see if it's feasible to brute-force the solution
In reply to @christianp
@christianp @icecolbeveridge update: it's quite easy
In reply to @icecolbeveridge
@icecolbeveridge I might be evil - currently computing hashes of all 8-digit numbers to see if it's feasible to brute-force the solution
In reply to @christianp
@christianp @icecolbeveridge update: it's quite easy